A given mass of gas occupies 2dm³ at 300k. At what temperature will its volume be doubled, keeping the pressure constant?

A. 400k
B. 480k
C. 550k
D. 600k

Correct Answer:

Option D – 600k

Explanation

At constant pressure connotes Charle’s law

V1T1 = V2T2

2dm³/300k = 2 x (2dm³/T2)

T2= 600k