A gas with initial volume of 2 X 10^-6 m³ is allowed to expand to six times its initial value at constant pressure of 2 x 10^5Nm−². The work done is?

A. 2.0J
B. 4. 0J
C. 12.0J
D. 2.4J

Correct Answer:

Option D = 2.4J

Explanation

P = F/A => F = PA = PV/L
W = FD = (PV/L) x L = PV
= 2 x 10⁵
(2 x 10^-6 x 6)
= 2 x 10⁵ x 1.2 x 10^-5
= 2.4 J