A. 2.5Ω
B. 5.0Ω
C. 8.0Ω
D. 10.0Ω
Correct Answer:
Option B = 5.0Ω
Explanation
r = resistance of the galvanometer
l = current through galvanometer = 20mA or 0.02A
V1 = p.d across the galvanometer = I X r = 0.02 X r
: V1 = 0.02r
V2 = p.d across the multiplier = 8 – 0.02r
R = resistance of the multiplier = 395Ω
where R = V/I
–> 395 = 8−0.02r0.02
CROSS MULTIPLY
8−0.02r = 395 * 0.02
8−0.02r = 7.9
–> 0.02r = 8 – 7.9
∴ r = 0.10.02
= 5Ω
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