A force of 500N is applied to a steel wire of cross-sectional area 0.2m². The tensile stress is?

A. 2.5×10^4Nm−²
B. 1.0×10²Nm−²
C. 1.0×10³Nm−²
D. 2.5×10³Nm−²

Correct Answer:

Option D – 2.5×10³Nm−²

Explanation

Stress=Force/Area

Stress=500/0.2 = 2500

= 2.5×10³Nm−²