A football is kicked at an angle of 45° to the horizontal over a defense line up with a velocity of 15ms−1. Calculate the magnitude of the horizontal velocity of the ball at its highest point [Neglect friction, g = 10ms−2].

A. 0.0ms−1
B. 5.6ms−1
C. 10.6ms−1
D. 15.0ms−1

Correct Answer: Option C

C. 10.6ms−1

Explanation

The horizontal component of velocity, Vx, is unaffected by the acceleration of free fall and remains constant.

Vx=Ux=Ucosθ
= 15×cos45=15×0.7071
≊10.6ms−1