A compound has an empirical formular CH2O and molecular mass of 90. [H = 1.00, C = 12.0, O = 16.0]

A. C4H10O2
B. C3H10O2
C. C3H6O3
D. C2H2O4

Correct Answer: Option C

C. C3H6O3

Explanation

(CH2O)n = 90

⇒ (12 + (1 x 2) + 16)n = 90
(12 + 2 + 16)n = 90; ⇒30n = 90;

n = 90/30; n = 3

(CH2O)3 = Molecular formula ; = C3H6O3