A body accelerates uniformly from rest at 2ms−2. Calculate its velocity when it has travelled a distance of 9m.

A. 3.0ms−1
B. 4.5ms−1
C. 6.0ms−1
D. 18.0ms−1

Correct Answer: Option C

C. 6.0ms−1

Explanation

Given that u=0ms−1,a=2ms‾², s=9m

We can use the equation, v²=u²+2as so that we have,

v²=0²+2×2×9
v²=36; v=6.0ms−1

Note; u = Initial velocity

v = final velocity

a = acceleration

s = distance covered