A. 3.0ms−1
B. 4.5ms−1
C. 6.0ms−1
D. 18.0ms−1
Correct Answer: Option C
C. 6.0ms−1
Explanation
Given that u=0ms−1,a=2ms‾², s=9m
We can use the equation, v²=u²+2as so that we have,
v²=0²+2×2×9
v²=36; v=6.0ms−1
Note; u = Initial velocity
v = final velocity
a = acceleration
s = distance covered
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