A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?

By: |Published on: Sep 2|Categories: Physics WAEC| 0 comments

A. 24.0V
B. 21.3V
C. 16.0V
D. 2.7V
E. 2.0V

Correct Answer:

Option B = 21.3V

Explanation

E = V + Ir
V = E- Ir
V = 24 – {(24/36) x 4}
V = 21.3V

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