A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2m/s. Determine the magnitude of the resulting impulse?

A. 20.0kgms−¹
B. 10.0kgms−¹
C. 5.0kgms−¹
D. 2.5kgms−¹

Correct Answer:

Option B – 10.0kgms−¹

Explanation

Impulse = Change in momentum

m (v – u)

5 (2.0)

= 5 x 2 = 10.0kgm−¹
= 10.0kgms−¹