8g of CH4 occupies 11.2 at S.T.P. What volume would 22g of CH3CH2CH3 occupy under the same condition?

A. 3.7dm³
B. 11.2dm³
C. 22.4dm³
D. 33dm³

Correct Answer:

Option B – 11.2dm³

Explanation

Molar mass of methane = 16g/mol

At S.T.P. its 8g occupies 11.2

so 16g occupies 22.4 dm³

Molar mass of propane = 44g/mol¹ occupies 22.4dm³ at S.T.P

so 22g will occupy 11.2dm³