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2kg Of Water Is Heated With A Heating Coil Which Draws 3.5A From A 200V Mains For 2 Minutes. What Is The Increase In Temperature Of The Water? [specific Heat Capacity Of Water = 4200 Jkg‾¹k‾¹] - Erudites Academy

A. 30°
B. 25°
C. 15°
D. 10°

Correct Answer:

Option D = 10°

Explanation

Electricity heat energy supplies by the heater = lvt = 3.5 x 200 x (2 x 60) = 84000J
and this heat is supplied to the 2 kg of the water MC ∆ t = 84000
2 x 4200 x ∆ t = 84000
∴ ∆t = (84000)/8400 = 10°c
∴ increase in temp. of water = 10°c

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