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0.5kg Of Water At 10ºC Is Completely Converted To Ice At 0ºC By Extracting (88000) Of Heat From It. If The Specific Heat Capacity Of Water Is 4200jkg¹ Cº. Calculate The Specific Latent Heat Of The Fusion Of Ice. - Erudites Academy

A. 9.0kjkg−1
B. 84.0kjkg−1
C. 134.0kjkg−1
D. 168.0kjkg−1

Correct Answer:

Option C = 134.0kjkg−1

Explanation

Heat involved (H) = 88,000J, Mass(M)= 0.5kg, specific heat capacity of water(C) = 4200JkgºC,

Specific latent heat of fusion(L) = ?, Temperature change(Δθ) = θ2 – θ1 = (10 – 0)° = 10°

H = MCΔθ + ML

or

H = M(CΔθ + L) –>H/M = CΔθ + L

: L = H/M – CΔθ = 88,000/0.5 – 4200 × 10

L = 176,000 – 42000 = 134,000

L = 134,000 or 134kj/kg

 

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